c++ vector에서 reallocation이 일어날 때 값들이 복사되나요? 이동하나요?

#include <iostream>
#include <vector>
using namespace std;
 
class base{
public:
    base() = default;
    ~base() = default;
    base(const base &b) noexcept { cout << b.name() << " is copied!"; }
    base(base &&b) noexcept { cout << b.name() << " is moved!"; }
 
    virtual const char *name() const noexcept { return "base"; }
};
 
class movable: public base{
public:
    movable() = default;
    ~movable() = default;
    movable(const movable &b) = default;
    movable(movable &&b) = default;
 
    virtual const char *name() const noexcept override { return "movable"; }
};
 
class noncopyable: public base{
public:
    noncopyable() = default;
    ~noncopyable() = default;
    noncopyable(const noncopyable &b) = delete;
    noncopyable(noncopyable &&b) = default;
 
    virtual const char *name() const noexcept override { return "noncopyable"; }
};
 
class nonmovable1: public base{
public:
    nonmovable1() = default;
    ~nonmovable1() = default;
    nonmovable1(const nonmovable1 &b) = default;
    nonmovable1(nonmovable1 &&b) = delete;
 
    virtual const char *name() const noexcept override { return "nonmovable1"; }
};
 
class nonmovable2: public base{
public:
    nonmovable2() = default;
    ~nonmovable2() = default;
    nonmovable2(const nonmovable2 &b) = default;
    nonmovable2(nonmovable2 &&b) noexcept(false) { /* Do nothing */ }
 
    virtual const char *name() const noexcept override { return "nonmovable2"; }
};
 
template <typename T>
static void move_test(){
    vector<T> v;
    v.emplace_back();
    v.shrink_to_fit();
    cout << "Test for " << T().name() << ":\n> ";
    v.emplace_back();
    cout << '\n';
}
 
int main(){
    move_test<movable>();
    move_test<noncopyable>();
    move_test<nonmovable1>();
    move_test<nonmovable2>();
    return 0;
}