[C++ 문법] template class가 있을 때, 해당 클래스의 member fuction을 다른 template class와 함께 specialization하기?

template <typename T>
class Field< Vector<T> >
{
   void out() const {
     ...
   }
};

#include <iostream>
using namespace std;
 
 
template <typename T>
class Vector
{
};
 
template <typename T>
class Field
{
public:
    void out() const;
};
 
template <typename T>
class Field< Vector<T> > : public Field<T>
{
public:
    void out() const
    {
        cout << "Field_Vector" << endl;
    }
};
 
template <>
void Field<double>::out() const
{
}
 
template <>
void Field<int>::out() const
{
    cout << "field_int" << endl;
}
 
int main()
{
    Field<int> f;
    f.out();
    Field< Vector<int> > fv;
    fv.out();
}
 
 
 
결과
field_int
Field_Vector